[Openmcl-devel] Error on macro character after sharpsign colon
gb at clozure.com
Wed Jan 27 13:18:51 UTC 2010
So, you think that
should quietly return an uninterned symbol whose name begins with a #
character, and that
should be read as an uninterned symbol with a 0-length name, followed
by an empty list ? (FWIW, SBCL has these behaviors; LW accepts the
first example and complains that the second involves a missing symbol
name after #:, allegro seems to treat both cases as SBCL does, CLISP
and CCL (and MCL) complain about both of these examples. I wouldn't
be surprised if other cases or a sampling of other implementations
expose other differences.)
That's indeed the behavior one would get if #: went directly to step
8 of the reader algorithm via something like your interpretation of
When you say that:
Now I think that 184.108.40.206 -- when it talks about "must have the syntax of
a symbol" -- that this statement can only imply that the thing after #:
is interpreted as a token as an a priori decision.
do you think that an a priori decision has also been made that the
alleged symbol name also contains no package prefix ?
"Must" can be interpreted in at least 2 ways:
(1) as "it is a requirement that" ("The arguments to the function
+ must be numbers, and it's desirable that #'+ verify that to
be true"). CLHS usually tries to use more precise terminology
to describe requirements like this.
(2) as "it is a logical consequence of previously established facts or
prior knowledge" ("If the sum of integers X and Y is known to be
odd and X is known to be even, then Y must be odd.")
It is certainly not established that the (alleged) symbol name doesn't
contain a package prefix; every implementation that I've looked at
treats that as something that needs to be verified at runtime. ("must
"). I find it odd that some implementations would treat the first
part as impling that something's been established (the the alleged
symbol name HAS the syntax of a symbol and we should enter a state
corresponding to step 8 of the reader algorithm based on some
nonexistent a priori knowledge of what characters actually follow #:).
I can't see how it's reasonable to simultaneously apply two disjoint
interpretations to a single use of the word "must".
It follows that I don't think that we have any reason to enter anything
other than a state corresponding to step 1 of the reader algorithm: we
don't know anything about the syntax types of the characters that we're
about to read and certainly haven't received special dispensation to
start in step 8; if we exit in from a state corresponding to step 10
(we have a token) we win and if we would exit in some other state we
lose (the characters following #: didn't have the syntax of a symbol);
if we won, we can check the additional requirement that the symbol name
token not have a package prefix.
In order to believe that there's a basis for going directly to step 8
(and treating initial non-terminating macro characters as constituents,
among other things), I have to parse a single use of "must" as if it
simultaneously means two different things. Every time that I try to
do that, I get a bad headache. If the restriction on package prefixes
weren't present, I think that I'd lean pretty far towards interpreting
"must have the syntax of a symbol" as meaning "it is a requirement that ..."
rather than "there is some unspecified basis for assuming that ..."; the
additional package-prefix qualification seems pretty convincing to
me (possibly because trying to lean in two directions at the same time
gives me a REALLY bad headache.)
On Wed, 27 Jan 2010, Tobias C. Rittweiler wrote:
> Gary Byers <gb at clozure.com> writes:
>> There are likely other reasons why calling the macro function either
>> can't work or wouldn't be a good idea. I don't think that any
>> implementations do that or that there's any reason to think that they
>> would. The #: reader-macro in the implementations whose source I
>> looked at do essentially what CCL does: collect a "token" by reading a
>> sequence of characters from the current input stream and making an
>> uninterned symbol out of the sequence of characters that comprise that
>> token. The "collect-token" process may involve calling some internal
>> function that's also called by the reader.
>> There are at least a couple of approaches to this token-collection
>> a) read characters and process escape characters until a delimiter
>> (whitespace, terminating macro, EOF) is encountered.
>> b) essentially the same, but insist that the first character is
>> a constituent or escape character (and not a non-terminating
>> Some implementations follow (a); others (including CCL) follow (b).
>> I haven't heard any argument in favor of (a) that doesn't seem to
>> be based on a misunderstanding of what's happening here.
> SBCL behaves like a), and I'd defend that as the "better" choice -- of
> course, I cannot give an official position statement, it's my personal
> 220.127.116.11 Sharpsign Colon says
> "The symbol-name must have the syntax of a symbol with no package
> The CLHS talks about "syntax of a symbol" only to differentiate tokens
> between numbers, potential numbers, and symbols. See for example:
> 2.3.1 Numbers as Tokens
> "When a token is read, it is interpreted as a number or symbol. The
> token is interpreted as a number if it satisfies the syntax for
> numbers specified in the next figure."
> 2.2 Reader Algorithm, 2nd §.
> "When dealing with tokens, the reader's basic function is to
> distinguish representations of symbols from those of numbers. When a
> token is accumulated, it is assumed to represent a number if it
> satisfies the syntax for numbers [...]. If it does not represent a
> number, it is then assumed to be a potential number if it satisfies
> the rules governing the syntax for a potential number. If a valid
> token is neither a representation of a number nor a potential number,
> it represents a symbol."
> Now I think that 18.104.22.168 -- when it talks about "must have the syntax of
> a symbol" -- that this statement can only imply that the thing after #:
> is interpreted as a token as an a priori decision.
> This means now, that #: must perform step 8 in the Reader Algorithm
> (2.2) which is the only place in the standard that specifies how tokens
> are actually read.
> Following step 8, a non-terminating macro character is just interpreted
> as constituent.
> I.e. taking the example in Terge's original posting, #:!foo must
> (following my argumentation) be read as an uninterned symbol with
> symbol-name "!FOO" (modulo readtable-case.)
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