[Openmcl-devel] Empty operands list on DIVISION-BY-ZERO signal

Gary Byers gb at clozure.com
Wed Jun 29 17:15:07 PDT 2011

The ARITHMETIC-ERROR-OPERATION in your example is LOG, not /.

? (log 0)
> Error: DIVISION-BY-ZERO detected
>        performing LOG on (0.0)

The spec defines ARITHMETIC-ERROR-OPERANDS and -OPERATION in terms of
"the offending call", but that term isn't well-defined.  A
floating-point exception can (and sometimes is) raised by explicitly
setting a bit in a status register, and if there's a "call" involved
in that process it may not be a lisp function call ...

I don't think that you can assume that the offending call when a
DIVISION-BY-ZERO occurs is always a two-operand call to #'/.  In cases

? (/ 0)


? (/ 1 2 0)

an implementation could legitimately consider the offending call to be
one with 1 or 3 operands.

You can probably assume that, if C is an ARITHMETIC-ERROR,


will generate the same type of ARITHMETIC-ERROR as C if that type of FP
exception is enabled.  I don't think that you can safely assume much more
than that.

On Wed, 29 Jun 2011, Gabriel Dos Reis wrote:

> On Wed, Jun 29, 2011 at 2:24 PM, Gabriel Dos Reis <gdr at open-axiom.net> wrote:
>> On Wed, Jun 22, 2011 at 3:19 AM, Gary Byers <gb at clozure.com> wrote:
>>> See <http://trac.clozure.com/ccl/ticket/871>.
>>> On Mon, 20 Jun 2011, Gabriel Dos Reis wrote:
>>>> Hi,
>>>> Clozure CL returns an empty list on the following form
>>>> (handler-case (/ 1 0) (division-by-zero (c) (arithmetic-error-operands
>>>> c)))
>> This appears indeed to be fixed on x86-64.
>> Thanks!
> One more thing: on DIVISION-BY-ZERO signal, how many arguments should
> I expect?  I (naively?) thought I would get two, but with the form
>    (handler-case (log 0) (division-by-zero (c) (arithmetic-error-operands c)))
> I get only one.  Two operands would have been more useful.
> -- Gaby

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